|ÁÖ¼Ò : ÀÎõ±¤¿ª½Ã ³²µ¿±¸ Æ÷±¸·Î 45 201µ¿ 111È£ (³íÇöµ¿, ³íÇöÀ¯È£¿£½ÃƼ 2´ÜÁö)
[¾ÆÆÄÆ®] ³íÇöµ¿ ³íÇöÀ¯È£¿£½ÃƼ2´ÜÁö(ÁÖ»óº¹ÇÕ) 201µ¿
|¸Å¹°Á¤º¸ (¸Å¹°¹øÈ£:129085110)
¼ÒÀçÁö ÀÎõ ³²µ¿±¸ ³íÇöµ¿
°Å·¡À¯Çü ¸Å¸Å
¸Å¸Å°¡°Ý 33,500¸¸¿ø
°ÇÃ๰¿ëµµ °øµ¿ÁÖÅÃ
¸éÀû 111.09§³ / 84.98§³
ÃѼ¼´ë¼ö 95¼¼´ë
¹æ/¿å½Ç¼ö 3°³ | 2°³
»ç¿ë½ÂÀÎÀÏ 2013³â 05¿ù 10ÀÏ
ÃÑ ÁÖÂ÷´ë¼ö 100´ë
ÇØ´çÃþ¼ö 2/20
¹æÇâ/Çö°ü±¸Á¶ ³²µ¿ | °è´Ü½Ä
ÀÔÁÖ°¡´ÉÀÏ 2025³â 09¿ù 31ÀÏ ÀÌÈÄ (ÇùÀǰ¡´É)
|À§Ä¡º¸±â